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321113021129 is a prime number
BaseRepresentation
bin1001010110000111101…
…00111101101011001001
31010200211220210121221122
410223003310331223021
520230114413134004
6403303422245025
732125323433655
oct4530364755311
91120756717848
10321113021129
11114201a2459a
1252298126775
1324385c95c14
1411783195a65
158545ed3cbe
hex4ac3d3dac9

321113021129 has 2 divisors, whose sum is σ = 321113021130. Its totient is φ = 321113021128.

The previous prime is 321113021101. The next prime is 321113021167. The reversal of 321113021129 is 921120311123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 321075223225 + 37797904 = 566635^2 + 6148^2 .

It is an emirp because it is prime and its reverse (921120311123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 321113021129 - 224 = 321096243913 is a prime.

It is a super-3 number, since 3×3211130211293 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 321113021098 and 321113021107.

It is not a weakly prime, because it can be changed into another prime (321113023129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160556510564 + 160556510565.

It is an arithmetic number, because the mean of its divisors is an integer number (160556510565).

Almost surely, 2321113021129 is an apocalyptic number.

It is an amenable number.

321113021129 is a deficient number, since it is larger than the sum of its proper divisors (1).

321113021129 is an equidigital number, since it uses as much as digits as its factorization.

321113021129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 26.

The spelling of 321113021129 in words is "three hundred twenty-one billion, one hundred thirteen million, twenty-one thousand, one hundred twenty-nine".