Base | Representation |
---|---|
bin | 11101111001111110… |
… | …111100000010010001 |
3 | 10001212220002201101102 |
4 | 131321332330002101 |
5 | 1011230444004131 |
6 | 22430212514145 |
7 | 2214514441313 |
oct | 357176740221 |
9 | 101786081342 |
10 | 32111313041 |
11 | 12688aa9845 |
12 | 628201b955 |
13 | 3049914362 |
14 | 17a89db7b3 |
15 | c7e1781cb |
hex | 779fbc091 |
32111313041 has 2 divisors, whose sum is σ = 32111313042. Its totient is φ = 32111313040.
The previous prime is 32111312999. The next prime is 32111313097. The reversal of 32111313041 is 14031311123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32066423041 + 44890000 = 179071^2 + 6700^2 .
It is a cyclic number.
It is not a de Polignac number, because 32111313041 - 26 = 32111312977 is a prime.
It is a super-3 number, since 3×321113130413 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (32111613041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16055656520 + 16055656521.
It is an arithmetic number, because the mean of its divisors is an integer number (16055656521).
Almost surely, 232111313041 is an apocalyptic number.
It is an amenable number.
32111313041 is a deficient number, since it is larger than the sum of its proper divisors (1).
32111313041 is an equidigital number, since it uses as much as digits as its factorization.
32111313041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 32111313041 its reverse (14031311123), we get a palindrome (46142624164).
The spelling of 32111313041 in words is "thirty-two billion, one hundred eleven million, three hundred thirteen thousand, forty-one".
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