3211132131131 has 2 divisors, whose sum is σ = 3211132131132. Its totient is φ = 3211132131130.

The previous prime is 3211132131127. The next prime is 3211132131197. The reversal of 3211132131131 is 1311312311123.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3211132131131 - 2² = 3211132131127 is a prime.

It is a super-3 number, since 3×3211132131131³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 3211132131097 and 3211132131106.

It is not a weakly prime, because it can be changed into another prime (3211132130131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605566065565 + 1605566065566.

It is an arithmetic number, because the mean of its divisors is an integer number (1605566065566).

Almost surely, 2^{3211132131131} is an apocalyptic number.

3211132131131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3211132131131 is an equidigital number, since it uses as much as digits as its factorization.

3211132131131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 324, while the sum is 23.

Adding to 3211132131131 its reverse (1311312311123), we get a palindrome (4522444442254).

The spelling of 3211132131131 in words is "three trillion, two hundred eleven billion, one hundred thirty-two million, one hundred thirty-one thousand, one hundred thirty-one".