Base | Representation |
---|---|
bin | 1110100110100100000000… |
… | …11111010111011101011001 |
3 | 11012200210221212212010010222 |
4 | 13103102000133113131121 |
5 | 13202103001242223342 |
6 | 152143424130245425 |
7 | 6522652502516525 |
oct | 723220037273531 |
9 | 135623855763128 |
10 | 32111331211097 |
11 | a260380367606 |
12 | 3727483a26875 |
13 | 14bc115c15798 |
14 | 7d02a7b46d85 |
15 | 3aa451ba6ed2 |
hex | 1d34807d7759 |
32111331211097 has 2 divisors, whose sum is σ = 32111331211098. Its totient is φ = 32111331211096.
The previous prime is 32111331211007. The next prime is 32111331211139. The reversal of 32111331211097 is 79011213311123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30969903933721 + 1141427277376 = 5565061^2 + 1068376^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32111331211097 is a prime.
It is a super-3 number, since 3×321113312110973 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (32111331211007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16055665605548 + 16055665605549.
It is an arithmetic number, because the mean of its divisors is an integer number (16055665605549).
Almost surely, 232111331211097 is an apocalyptic number.
It is an amenable number.
32111331211097 is a deficient number, since it is larger than the sum of its proper divisors (1).
32111331211097 is an equidigital number, since it uses as much as digits as its factorization.
32111331211097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 35.
The spelling of 32111331211097 in words is "thirty-two trillion, one hundred eleven billion, three hundred thirty-one million, two hundred eleven thousand, ninety-seven".
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