Base | Representation |
---|---|
bin | 11101111010000001… |
… | …101000111010000001 |
3 | 10001212221102200200121 |
4 | 131322001220322001 |
5 | 1011231134133441 |
6 | 22430240020241 |
7 | 2214523450555 |
oct | 357201507201 |
9 | 101787380617 |
10 | 32112021121 |
11 | 12689442834 |
12 | 6282301681 |
13 | 3049b0173b |
14 | 17a8b43865 |
15 | c7e267dd1 |
hex | 77a068e81 |
32112021121 has 2 divisors, whose sum is σ = 32112021122. Its totient is φ = 32112021120.
The previous prime is 32112021043. The next prime is 32112021169. The reversal of 32112021121 is 12112021123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27272871025 + 4839150096 = 165145^2 + 69564^2 .
It is a cyclic number.
It is not a de Polignac number, because 32112021121 - 223 = 32103632513 is a prime.
It is a super-4 number, since 4×321120211214 (a number of 43 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32112021095 and 32112021104.
It is not a weakly prime, because it can be changed into another prime (32112081121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056010560 + 16056010561.
It is an arithmetic number, because the mean of its divisors is an integer number (16056010561).
Almost surely, 232112021121 is an apocalyptic number.
It is an amenable number.
32112021121 is a deficient number, since it is larger than the sum of its proper divisors (1).
32112021121 is an equidigital number, since it uses as much as digits as its factorization.
32112021121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 32112021121 its reverse (12112021123), we get a palindrome (44224042244).
The spelling of 32112021121 in words is "thirty-two billion, one hundred twelve million, twenty-one thousand, one hundred twenty-one".
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