Base | Representation |
---|---|
bin | 1110100110100101100000… |
… | …00110100101001100100010 |
3 | 11012200220000112221211010201 |
4 | 13103102300012211030202 |
5 | 13202111120241121010 |
6 | 152144035303415414 |
7 | 6523011342343036 |
oct | 723226006451442 |
9 | 135626015854121 |
10 | 32112130020130 |
11 | a260750264666 |
12 | 372766745456a |
13 | 14bc21256c554 |
14 | 7d0341c821c6 |
15 | 3aa49bd9623a |
hex | 1d34b01a5322 |
32112130020130 has 8 divisors (see below), whose sum is σ = 57801834036252. Its totient is φ = 12844852008048.
The previous prime is 32112130020041. The next prime is 32112130020143. The reversal of 32112130020130 is 3102003121123.
It can be written as a sum of positive squares in 2 ways, for example, as 31853302440129 + 258827580001 = 5643873^2 + 508751^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 32112130020098 and 32112130020107.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1605606500997 + ... + 1605606501016.
Almost surely, 232112130020130 is an apocalyptic number.
32112130020130 is a deficient number, since it is larger than the sum of its proper divisors (25689704016122).
32112130020130 is a wasteful number, since it uses less digits than its factorization.
32112130020130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3211213002020.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 32112130020130 its reverse (3102003121123), we get a palindrome (35214133141253).
The spelling of 32112130020130 in words is "thirty-two trillion, one hundred twelve billion, one hundred thirty million, twenty thousand, one hundred thirty".
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