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32113103000000 = 2656119673019
BaseRepresentation
bin1110100110100111010100…
…00110001101000111000000
311012200222112100210022121012
413103103222012031013000
513202120113332000000
6152144320022020052
76523044425466041
oct723235206150700
9135628470708535
1032113103000000
11a2610aa502860
123727899277628
1314bc339008b99
147d03d51988c8
153aa5074db735
hex1d34ea18d1c0

32113103000000 has 392 divisors, whose sum is σ = 87014523699840. Its totient is φ = 11661552000000.

The previous prime is 32113102999993. The next prime is 32113103000003. The reversal of 32113103000000 is 30131123.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32113103000003) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 10636998491 + ... + 10637001509.

Almost surely, 232113103000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 32113103000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (43507261849920).

32113103000000 is an abundant number, since it is smaller than the sum of its proper divisors (54901420699840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

32113103000000 is an frugal number, since it uses more digits than its factorization.

32113103000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4039 (or 4004 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 32113103000000 its reverse (30131123), we get a palindrome (32113133131123).

The spelling of 32113103000000 in words is "thirty-two trillion, one hundred thirteen billion, one hundred three million", and thus it is an aban number.