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32113302241331 is a prime number
BaseRepresentation
bin1110100110100111101011…
…11110010000000000110011
311012201000001020200211022202
413103103311332100000303
513202121020333210311
6152144351500253415
76523052365143413
oct723236576200063
9135630036624282
1032113302241331
11a2611a1a17813
123727933b4126b
1314bc36b388a6c
147d0413820643
153aa519c45e3b
hex1d34f5f90033

32113302241331 has 2 divisors, whose sum is σ = 32113302241332. Its totient is φ = 32113302241330.

The previous prime is 32113302241301. The next prime is 32113302241343. The reversal of 32113302241331 is 13314220331123.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32113302241331 is a prime.

It is a super-2 number, since 2×321133022413312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 32113302241294 and 32113302241303.

It is not a weakly prime, because it can be changed into another prime (32113302241301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056651120665 + 16056651120666.

It is an arithmetic number, because the mean of its divisors is an integer number (16056651120666).

Almost surely, 232113302241331 is an apocalyptic number.

32113302241331 is a deficient number, since it is larger than the sum of its proper divisors (1).

32113302241331 is an equidigital number, since it uses as much as digits as its factorization.

32113302241331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 32113302241331 its reverse (13314220331123), we get a palindrome (45427522572454).

The spelling of 32113302241331 in words is "thirty-two trillion, one hundred thirteen billion, three hundred two million, two hundred forty-one thousand, three hundred thirty-one".