3211413000000 has 196 divisors, whose sum is σ = 10620953425056. Its totient is φ = 856376000000.

The previous prime is 3211412999939. The next prime is 3211413000001. The reversal of 3211413000000 is 3141123.

3211413000000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3211413000001) by changing a digit.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 2464765 + ... + 3535235.

Almost surely, 2^{3211413000000} is an apocalyptic number.

3211413000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3211413000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5310476712528).

3211413000000 is an abundant number, since it is smaller than the sum of its proper divisors (7409540425056).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3211413000000 is an frugal number, since it uses more digits than its factorization.

3211413000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1070516 (or 1070481 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 3211413000000 its reverse (3141123), we get a palindrome (3211416141123).

The spelling of 3211413000000 in words is "three trillion, two hundred eleven billion, four hundred thirteen million", and thus it is an aban number.