Base | Representation |
---|---|
bin | 1110100110101001100100… |
… | …00111101010000001000011 |
3 | 11012201002122120111100121012 |
4 | 13103110302013222001003 |
5 | 13202130102200340344 |
6 | 152145035544551135 |
7 | 6523116400301342 |
oct | 723246207520103 |
9 | 135632576440535 |
10 | 32114311340099 |
11 | a26166a59563a |
12 | 3727b75a824ab |
13 | 14bc49c460521 |
14 | 7d04ab859b59 |
15 | 3aa57862329e |
hex | 1d35321ea043 |
32114311340099 has 2 divisors, whose sum is σ = 32114311340100. Its totient is φ = 32114311340098.
The previous prime is 32114311340009. The next prime is 32114311340113. The reversal of 32114311340099 is 99004311341123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32114311340099 - 28 = 32114311339843 is a prime.
It is a super-2 number, since 2×321143113400992 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (32114311340009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16057155670049 + 16057155670050.
It is an arithmetic number, because the mean of its divisors is an integer number (16057155670050).
Almost surely, 232114311340099 is an apocalyptic number.
32114311340099 is a deficient number, since it is larger than the sum of its proper divisors (1).
32114311340099 is an equidigital number, since it uses as much as digits as its factorization.
32114311340099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 41.
The spelling of 32114311340099 in words is "thirty-two trillion, one hundred fourteen billion, three hundred eleven million, three hundred forty thousand, ninety-nine".
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