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32114311340099 is a prime number
BaseRepresentation
bin1110100110101001100100…
…00111101010000001000011
311012201002122120111100121012
413103110302013222001003
513202130102200340344
6152145035544551135
76523116400301342
oct723246207520103
9135632576440535
1032114311340099
11a26166a59563a
123727b75a824ab
1314bc49c460521
147d04ab859b59
153aa57862329e
hex1d35321ea043

32114311340099 has 2 divisors, whose sum is σ = 32114311340100. Its totient is φ = 32114311340098.

The previous prime is 32114311340009. The next prime is 32114311340113. The reversal of 32114311340099 is 99004311341123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32114311340099 - 28 = 32114311339843 is a prime.

It is a super-2 number, since 2×321143113400992 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (32114311340009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16057155670049 + 16057155670050.

It is an arithmetic number, because the mean of its divisors is an integer number (16057155670050).

Almost surely, 232114311340099 is an apocalyptic number.

32114311340099 is a deficient number, since it is larger than the sum of its proper divisors (1).

32114311340099 is an equidigital number, since it uses as much as digits as its factorization.

32114311340099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 32114311340099 in words is "thirty-two trillion, one hundred fourteen billion, three hundred eleven million, three hundred forty thousand, ninety-nine".