Base | Representation |
---|---|
bin | 1110100110110100100011… |
… | …10001000111011011111011 |
3 | 11012201122212201202201001211 |
4 | 13103122101301013123323 |
5 | 13202224143004330243 |
6 | 152151453215223551 |
7 | 6523415525545111 |
oct | 723322161073373 |
9 | 135648781681054 |
10 | 32120211011323 |
11 | a26411781a986 |
12 | 3729141817bb7 |
13 | 14bcbcc7cbc46 |
14 | 7d08ab1cdab1 |
15 | 3aa7c153dd9d |
hex | 1d3691c476fb |
32120211011323 has 2 divisors, whose sum is σ = 32120211011324. Its totient is φ = 32120211011322.
The previous prime is 32120211011303. The next prime is 32120211011327. The reversal of 32120211011323 is 32311011202123.
It is a strong prime.
It is an emirp because it is prime and its reverse (32311011202123) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32120211011323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32120211011294 and 32120211011303.
It is not a weakly prime, because it can be changed into another prime (32120211011327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16060105505661 + 16060105505662.
It is an arithmetic number, because the mean of its divisors is an integer number (16060105505662).
Almost surely, 232120211011323 is an apocalyptic number.
32120211011323 is a deficient number, since it is larger than the sum of its proper divisors (1).
32120211011323 is an equidigital number, since it uses as much as digits as its factorization.
32120211011323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 32120211011323 its reverse (32311011202123), we get a palindrome (64431222213446).
The spelling of 32120211011323 in words is "thirty-two trillion, one hundred twenty billion, two hundred eleven million, eleven thousand, three hundred twenty-three".
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