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3212042023433 is a prime number
BaseRepresentation
bin101110101111011100100…
…111111011001000001001
3102101001211201202010121102
4232233130213323020021
5410111230224222213
610455331451551145
7451030252501115
oct56573447731011
912331751663542
103212042023433
111029245a91361
1243a62245b4b5
131a3b81908419
14b166c414745
1558844e8a158
hex2ebdc9fb209

3212042023433 has 2 divisors, whose sum is σ = 3212042023434. Its totient is φ = 3212042023432.

The previous prime is 3212042023381. The next prime is 3212042023469. The reversal of 3212042023433 is 3343202402123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3206667374089 + 5374649344 = 1790717^2 + 73312^2 .

It is a cyclic number.

It is not a de Polignac number, because 3212042023433 - 26 = 3212042023369 is a prime.

It is a super-2 number, since 2×32120420234332 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3212042023396 and 3212042023405.

It is not a weakly prime, because it can be changed into another prime (3212042023733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606021011716 + 1606021011717.

It is an arithmetic number, because the mean of its divisors is an integer number (1606021011717).

Almost surely, 23212042023433 is an apocalyptic number.

It is an amenable number.

3212042023433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212042023433 is an equidigital number, since it uses as much as digits as its factorization.

3212042023433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 3212042023433 its reverse (3343202402123), we get a palindrome (6555244425556).

The spelling of 3212042023433 in words is "three trillion, two hundred twelve billion, forty-two million, twenty-three thousand, four hundred thirty-three".