Base | Representation |
---|---|
bin | 1110100110110110100101… |
… | …01100011110000001000011 |
3 | 11012201202200122110220212012 |
4 | 13103123102230132001003 |
5 | 13202233410334442011 |
6 | 152152153250523135 |
7 | 6523454523500162 |
oct | 723332254360103 |
9 | 135652618426765 |
10 | 32121300312131 |
11 | a264626697788 |
12 | 37293a65964ab |
13 | 14c00443a4a34 |
14 | 7d0971b453d9 |
15 | 3aa836eaea8b |
hex | 1d36d2b1e043 |
32121300312131 has 2 divisors, whose sum is σ = 32121300312132. Its totient is φ = 32121300312130.
The previous prime is 32121300312077. The next prime is 32121300312139. The reversal of 32121300312131 is 13121300312123.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32121300312131 is a prime.
It is a super-2 number, since 2×321213003121312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32121300312097 and 32121300312106.
It is not a weakly prime, because it can be changed into another prime (32121300312139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16060650156065 + 16060650156066.
It is an arithmetic number, because the mean of its divisors is an integer number (16060650156066).
Almost surely, 232121300312131 is an apocalyptic number.
32121300312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
32121300312131 is an equidigital number, since it uses as much as digits as its factorization.
32121300312131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 32121300312131 its reverse (13121300312123), we get a palindrome (45242600624254).
The spelling of 32121300312131 in words is "thirty-two trillion, one hundred twenty-one billion, three hundred million, three hundred twelve thousand, one hundred thirty-one".
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