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3212132022114 = 23535355337019
BaseRepresentation
bin101110101111100001111…
…111001111011101100010
3102101002002000002112120220
4232233201333033131202
5410111421244201424
610455344424543510
7451032424460001
oct56574177173542
912332060075526
103212132022114
111029291871734
1243a648621b96
131a3b97459892
14b167a360c38
155884cd16579
hex2ebe1fcf762

3212132022114 has 8 divisors (see below), whose sum is σ = 6424264044240. Its totient is φ = 1070710674036.

The previous prime is 3212132022097. The next prime is 3212132022131. The reversal of 3212132022114 is 4112202312123.

It is an interprime number because it is at equal distance from previous prime (3212132022097) and next prime (3212132022131).

It is a sphenic number, since it is the product of 3 distinct primes.

3212132022114 is an admirable number.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 267677668504 + ... + 267677668515.

It is an arithmetic number, because the mean of its divisors is an integer number (803033005530).

Almost surely, 23212132022114 is an apocalyptic number.

3212132022114 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3212132022114 is a wasteful number, since it uses less digits than its factorization.

3212132022114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 535355337024.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 3212132022114 its reverse (4112202312123), we get a palindrome (7324334334237).

The spelling of 3212132022114 in words is "three trillion, two hundred twelve billion, one hundred thirty-two million, twenty-two thousand, one hundred fourteen".

Divisors: 1 2 3 6 535355337019 1070710674038 1606066011057 3212132022114