Base | Representation |
---|---|
bin | 101110101111101100000… |
… | …100111111000100100001 |
3 | 102101002111210121202012021 |
4 | 232233230010333010201 |
5 | 410112243113100001 |
6 | 10455413313101441 |
7 | 451036551350353 |
oct | 56575404770441 |
9 | 12332453552167 |
10 | 3212301300001 |
11 | 1029369380712 |
12 | 43a695257881 |
13 | 1a3bc3548301 |
14 | b1694a270d3 |
15 | 5885cb02ba1 |
hex | 2ebec13f121 |
3212301300001 has 2 divisors, whose sum is σ = 3212301300002. Its totient is φ = 3212301300000.
The previous prime is 3212301299971. The next prime is 3212301300007. The reversal of 3212301300001 is 1000031032123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2486739763600 + 725561536401 = 1576940^2 + 851799^2 .
It is a cyclic number.
It is not a de Polignac number, because 3212301300001 - 215 = 3212301267233 is a prime.
It is a super-2 number, since 2×32123013000012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3212301300007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606150650000 + 1606150650001.
It is an arithmetic number, because the mean of its divisors is an integer number (1606150650001).
Almost surely, 23212301300001 is an apocalyptic number.
It is an amenable number.
3212301300001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3212301300001 is an equidigital number, since it uses as much as digits as its factorization.
3212301300001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 3212301300001 its reverse (1000031032123), we get a palindrome (4212332332124).
The spelling of 3212301300001 in words is "three trillion, two hundred twelve billion, three hundred one million, three hundred thousand, one".
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