Base | Representation |
---|---|
bin | 1110100110111001111111… |
… | …10100110101000010000111 |
3 | 11012201221102020122200102120 |
4 | 13103130333310311002013 |
5 | 13202301133043020403 |
6 | 152153055053341023 |
7 | 6523551065114250 |
oct | 723347764650207 |
9 | 135657366580376 |
10 | 32123131220103 |
11 | a265386141a70 |
12 | 3729817797773 |
13 | 14c02767c7131 |
14 | 7d0aa6d85b27 |
15 | 3aa8e2ac0e53 |
hex | 1d373fd35087 |
32123131220103 has 16 divisors (see below), whose sum is σ = 53399490859776. Its totient is φ = 16687340893440.
The previous prime is 32123131220077. The next prime is 32123131220153. The reversal of 32123131220103 is 30102213132123.
It is not a de Polignac number, because 32123131220103 - 28 = 32123131219847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32123131220153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69530586826 + ... + 69530587287.
It is an arithmetic number, because the mean of its divisors is an integer number (3337468178736).
Almost surely, 232123131220103 is an apocalyptic number.
32123131220103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
32123131220103 is a deficient number, since it is larger than the sum of its proper divisors (21276359639673).
32123131220103 is a wasteful number, since it uses less digits than its factorization.
32123131220103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139061174134.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 32123131220103 its reverse (30102213132123), we get a palindrome (62225344352226).
The spelling of 32123131220103 in words is "thirty-two trillion, one hundred twenty-three billion, one hundred thirty-one million, two hundred twenty thousand, one hundred three".
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