Base | Representation |
---|---|
bin | 11101111010110000… |
… | …100001101001000101 |
3 | 10001220210120010210021 |
4 | 131322300201221011 |
5 | 1011242310442013 |
6 | 22431355255141 |
7 | 2215033101454 |
oct | 357260415105 |
9 | 101823503707 |
10 | 32124312133 |
11 | 126953781a1 |
12 | 628644a4b1 |
13 | 304c516024 |
14 | 17aa622b9b |
15 | c80394a8d |
hex | 77ac21a45 |
32124312133 has 8 divisors (see below), whose sum is σ = 32207922936. Its totient is φ = 32040811200.
The previous prime is 32124312119. The next prime is 32124312151. The reversal of 32124312133 is 33121342123.
It can be written as a sum of positive squares in 4 ways, for example, as 4615435969 + 27508876164 = 67937^2 + 165858^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 32124312133 - 233 = 23534377541 is a prime.
It is a super-2 number, since 2×321243121332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 32124312098 and 32124312107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32124312113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 575103 + ... + 628483.
It is an arithmetic number, because the mean of its divisors is an integer number (4025990367).
Almost surely, 232124312133 is an apocalyptic number.
It is an amenable number.
32124312133 is a deficient number, since it is larger than the sum of its proper divisors (83610803).
32124312133 is an equidigital number, since it uses as much as digits as its factorization.
32124312133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54935.
The product of its digits is 2592, while the sum is 25.
Adding to 32124312133 its reverse (33121342123), we get a palindrome (65245654256).
The spelling of 32124312133 in words is "thirty-two billion, one hundred twenty-four million, three hundred twelve thousand, one hundred thirty-three".
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