Base | Representation |
---|---|
bin | 101110101111111000101… |
… | …001001101110001110111 |
3 | 102101010001111022201101101 |
4 | 232233320221031301313 |
5 | 410113211100432043 |
6 | 10455450243510531 |
7 | 451045021335556 |
oct | 56577051156167 |
9 | 12333044281341 |
10 | 3212512124023 |
11 | 1029467386944 |
12 | 43a733988447 |
13 | 1a3c28122257 |
14 | b16b4a25d9d |
15 | 5887139924d |
hex | 2ebf8a4dc77 |
3212512124023 has 4 divisors (see below), whose sum is σ = 3215151822960. Its totient is φ = 3209872425088.
The previous prime is 3212512123999. The next prime is 3212512124051. The reversal of 3212512124023 is 3204212152123.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3212512124023 - 213 = 3212512115831 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3212512123982 and 3212512124000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3212512124053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1319847643 + ... + 1319850076.
It is an arithmetic number, because the mean of its divisors is an integer number (803787955740).
Almost surely, 23212512124023 is an apocalyptic number.
3212512124023 is a deficient number, since it is larger than the sum of its proper divisors (2639698937).
3212512124023 is a wasteful number, since it uses less digits than its factorization.
3212512124023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2639698936.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 3212512124023 its reverse (3204212152123), we get a palindrome (6416724276146).
The spelling of 3212512124023 in words is "three trillion, two hundred twelve billion, five hundred twelve million, one hundred twenty-four thousand, twenty-three".
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