Base | Representation |
---|---|
bin | 1110100110111110010010… |
… | …11100100000011100010011 |
3 | 11012202011101011012221101002 |
4 | 13103133021130200130103 |
5 | 13202320400131200430 |
6 | 152154120132532215 |
7 | 6523662232221665 |
oct | 723371134403423 |
9 | 135664334187332 |
10 | 32125440100115 |
11 | a26636047876a |
12 | 372a160a8106b |
13 | 14c0553c5b11b |
14 | 7d0c45886535 |
15 | 3aa9ca648845 |
hex | 1d37c9720713 |
32125440100115 has 64 divisors (see below), whose sum is σ = 42317887328640. Its totient is φ = 23315277250560.
The previous prime is 32125440100109. The next prime is 32125440100141. The reversal of 32125440100115 is 51100104452123.
It is a happy number.
It is not a de Polignac number, because 32125440100115 - 218 = 32125439837971 is a prime.
It is a super-2 number, since 2×321254401001152 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 138974351 + ... + 139205319.
It is an arithmetic number, because the mean of its divisors is an integer number (661216989510).
Almost surely, 232125440100115 is an apocalyptic number.
32125440100115 is a deficient number, since it is larger than the sum of its proper divisors (10192447228525).
32125440100115 is a wasteful number, since it uses less digits than its factorization.
32125440100115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 231512.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 32125440100115 its reverse (51100104452123), we get a palindrome (83225544552238).
The spelling of 32125440100115 in words is "thirty-two trillion, one hundred twenty-five billion, four hundred forty million, one hundred thousand, one hundred fifteen".
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