Base | Representation |
---|---|
bin | 1110100110111110010101… |
… | …10111110110010111001001 |
3 | 11012202011102211021110120201 |
4 | 13103133022313312113021 |
5 | 13202320422243420001 |
6 | 152154122350052201 |
7 | 6523662642601105 |
oct | 723371267662711 |
9 | 135664384243521 |
10 | 32125464045001 |
11 | a266372a42928 |
12 | 372a168aaa061 |
13 | 14c0558bc2cb2 |
14 | 7d0c48b1a905 |
15 | 3aa9cc7c8501 |
hex | 1d37cadf65c9 |
32125464045001 has 2 divisors, whose sum is σ = 32125464045002. Its totient is φ = 32125464045000.
The previous prime is 32125464044951. The next prime is 32125464045079. The reversal of 32125464045001 is 10054046452123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29354171366601 + 2771292678400 = 5417949^2 + 1664720^2 .
It is a cyclic number.
It is not a de Polignac number, because 32125464045001 - 231 = 32123316561353 is a prime.
It is not a weakly prime, because it can be changed into another prime (32125464345001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16062732022500 + 16062732022501.
It is an arithmetic number, because the mean of its divisors is an integer number (16062732022501).
Almost surely, 232125464045001 is an apocalyptic number.
It is an amenable number.
32125464045001 is a deficient number, since it is larger than the sum of its proper divisors (1).
32125464045001 is an equidigital number, since it uses as much as digits as its factorization.
32125464045001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 37.
The spelling of 32125464045001 in words is "thirty-two trillion, one hundred twenty-five billion, four hundred sixty-four million, forty-five thousand, one".
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