Base | Representation |
---|---|
bin | 100100100001110000111110… |
… | …1001010001110100010010011 |
3 | 1120010121222111100210212120111 |
4 | 1021003201331022032202103 |
5 | 314103134411401442042 |
6 | 3055203104411222151 |
7 | 124451105565366322 |
oct | 11103417512164223 |
9 | 1503558440725514 |
10 | 321300013312147 |
11 | 93415630271321 |
12 | 30052118447957 |
13 | 10a385cc49429c |
14 | 594b009d060b9 |
15 | 2722b3d899517 |
hex | 124387d28e893 |
321300013312147 has 2 divisors, whose sum is σ = 321300013312148. Its totient is φ = 321300013312146.
The previous prime is 321300013312133. The next prime is 321300013312193. The reversal of 321300013312147 is 741213310003123.
It is a weak prime.
It is an emirp because it is prime and its reverse (741213310003123) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-321300013312147 is a prime.
It is not a weakly prime, because it can be changed into another prime (321300013312847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160650006656073 + 160650006656074.
It is an arithmetic number, because the mean of its divisors is an integer number (160650006656074).
Almost surely, 2321300013312147 is an apocalyptic number.
321300013312147 is a deficient number, since it is larger than the sum of its proper divisors (1).
321300013312147 is an equidigital number, since it uses as much as digits as its factorization.
321300013312147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
The spelling of 321300013312147 in words is "three hundred twenty-one trillion, three hundred billion, thirteen million, three hundred twelve thousand, one hundred forty-seven".
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