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3213004151055 = 35214200276737
BaseRepresentation
bin101110110000010101111…
…110001001100100001111
3102101011022210011021120210
4232300111332021210033
5410120213030313210
610500011141413503
7451063144444656
oct56602576114417
912334283137523
103213004151055
11102969a098056
1243a85070a293
131a3ca60452ca
14b172010419d
155889e689e20
hex2ec15f8990f

3213004151055 has 8 divisors (see below), whose sum is σ = 5140806641712. Its totient is φ = 1713602213888.

The previous prime is 3213004150963. The next prime is 3213004151117. The reversal of 3213004151055 is 5501514003123.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3213004151055 - 220 = 3213003102479 is a prime.

It is a super-2 number, since 2×32130041510552 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 107100138354 + ... + 107100138383.

It is an arithmetic number, because the mean of its divisors is an integer number (642600830214).

Almost surely, 23213004151055 is an apocalyptic number.

3213004151055 is a deficient number, since it is larger than the sum of its proper divisors (1927802490657).

3213004151055 is a wasteful number, since it uses less digits than its factorization.

3213004151055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214200276745.

The product of its (nonzero) digits is 9000, while the sum is 30.

Adding to 3213004151055 its reverse (5501514003123), we get a palindrome (8714518154178).

The spelling of 3213004151055 in words is "three trillion, two hundred thirteen billion, four million, one hundred fifty-one thousand, fifty-five".

Divisors: 1 3 5 15 214200276737 642600830211 1071001383685 3213004151055