Base | Representation |
---|---|
bin | 1110100111000111000000… |
… | …11100110110010101100001 |
3 | 11012202121110101012222012211 |
4 | 13103203200130312111201 |
5 | 13202404441441024212 |
6 | 152200212425322121 |
7 | 6524216231414545 |
oct | 723434034662541 |
9 | 135677411188184 |
10 | 32130121033057 |
11 | a268342768993 |
12 | 372b048636341 |
13 | 14c0b1b974328 |
14 | 7d116b40da25 |
15 | 3aaba15769a7 |
hex | 1d38e0736561 |
32130121033057 has 2 divisors, whose sum is σ = 32130121033058. Its totient is φ = 32130121033056.
The previous prime is 32130121033001. The next prime is 32130121033111. The reversal of 32130121033057 is 75033012103123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28879542812961 + 3250578220096 = 5373969^2 + 1802936^2 .
It is a cyclic number.
It is not a de Polignac number, because 32130121033057 - 211 = 32130121031009 is a prime.
It is not a weakly prime, because it can be changed into another prime (32130121037057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065060516528 + 16065060516529.
It is an arithmetic number, because the mean of its divisors is an integer number (16065060516529).
Almost surely, 232130121033057 is an apocalyptic number.
It is an amenable number.
32130121033057 is a deficient number, since it is larger than the sum of its proper divisors (1).
32130121033057 is an equidigital number, since it uses as much as digits as its factorization.
32130121033057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 31.
The spelling of 32130121033057 in words is "thirty-two trillion, one hundred thirty billion, one hundred twenty-one million, thirty-three thousand, fifty-seven".
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