3213012433 has 2 divisors, whose sum is σ = 3213012434. Its totient is φ = 3213012432.

The previous prime is 3213012421. The next prime is 3213012443. The reversal of 3213012433 is 3342103123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2131391889 + 1081620544 = 46167^2 + 32888^2 .

It is an emirp because it is prime and its reverse (3342103123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3213012433 - 2²⁵ = 3179458001 is a prime.

It is a super-2 number, since 2×3213012433² = 20646897789225158978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3213012443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606506216 + 1606506217.

It is an arithmetic number, because the mean of its divisors is an integer number (1606506217).

Almost surely, 2^3213012433 is an apocalyptic number.

It is an amenable number.

3213012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3213012433 is an equidigital number, since it uses as much as digits as its factorization.

3213012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 22.

The square root of 3213012433 is about 56683.4405536573. The cubic root of 3213012433 is about 1475.6073236656.

Adding to 3213012433 its reverse (3342103123), we get a palindrome (6555115556).

The spelling of 3213012433 in words is "three billion, two hundred thirteen million, twelve thousand, four hundred thirty-three".