3213012441433 has 16 divisors (see below), whose sum is σ = 3475461441024. Its totient is φ = 2958763806720.

The previous prime is 3213012441413. The next prime is 3213012441481. The reversal of 3213012441433 is 3341442103123.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3213012441433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3213012441395 and 3213012441404.

It is not an unprimeable number, because it can be changed into a prime (3213012441413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1998841 + ... + 3228217.

It is an arithmetic number, because the mean of its divisors is an integer number (217216340064).

Almost surely, 2^{3213012441433} is an apocalyptic number.

It is an amenable number.

3213012441433 is a deficient number, since it is larger than the sum of its proper divisors (262448999591).

3213012441433 is a wasteful number, since it uses less digits than its factorization.

3213012441433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1232712.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 3213012441433 its reverse (3341442103123), we get a palindrome (6554454544556).

The spelling of 3213012441433 in words is "three trillion, two hundred thirteen billion, twelve million, four hundred forty-one thousand, four hundred thirty-three".