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3213012441481 is a prime number
BaseRepresentation
bin101110110000010110011…
…101110001100110001001
3102101011100100202110220121
4232300112131301212021
5410120222141111411
610500012035223241
7451063305064213
oct56602635614611
912334310673817
103213012441481
1110296a383a847
1243a853447b21
131a3ca798899b
14b17212615b3
15588a0276571
hex2ec16771989

3213012441481 has 2 divisors, whose sum is σ = 3213012441482. Its totient is φ = 3213012441480.

The previous prime is 3213012441413. The next prime is 3213012441517. The reversal of 3213012441481 is 1841442103123.

3213012441481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3212859078025 + 153363456 = 1792445^2 + 12384^2 .

It is a cyclic number.

It is not a de Polignac number, because 3213012441481 - 29 = 3213012440969 is a prime.

It is a super-2 number, since 2×32130124414812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3213012441781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606506220740 + 1606506220741.

It is an arithmetic number, because the mean of its divisors is an integer number (1606506220741).

Almost surely, 23213012441481 is an apocalyptic number.

It is an amenable number.

3213012441481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3213012441481 is an equidigital number, since it uses as much as digits as its factorization.

3213012441481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 34.

The spelling of 3213012441481 in words is "three trillion, two hundred thirteen billion, twelve million, four hundred forty-one thousand, four hundred eighty-one".