3213012513111 has 4 divisors (see below), whose sum is σ = 4284016684152. Its totient is φ = 2142008342072.

The previous prime is 3213012513101. The next prime is 3213012513119. The reversal of 3213012513111 is 1113152103123.

3213012513111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3213012513111 - 2⁹ = 3213012512599 is a prime.

It is a super-4 number, since 4×3213012513111⁴ (a number of 51 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3213012513119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 535502085516 + ... + 535502085521.

It is an arithmetic number, because the mean of its divisors is an integer number (1071004171038).

Almost surely, 2^{3213012513111} is an apocalyptic number.

3213012513111 is a deficient number, since it is larger than the sum of its proper divisors (1071004171041).

3213012513111 is a wasteful number, since it uses less digits than its factorization.

3213012513111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1071004171040.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 3213012513111 its reverse (1113152103123), we get a palindrome (4326164616234).

The spelling of 3213012513111 in words is "three trillion, two hundred thirteen billion, twelve million, five hundred thirteen thousand, one hundred eleven".