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32131013153 is a prime number
BaseRepresentation
bin11101111011001010…
…000101101000100001
310001221021011120212012
4131323022011220201
51011301014410103
622432155042305
72215144051121
oct357312055041
9101837146765
1032131013153
1112699134828
126288740395
133050a21125
1417ab488c81
15c80c6a2d8
hex77b285a21

32131013153 has 2 divisors, whose sum is σ = 32131013154. Its totient is φ = 32131013152.

The previous prime is 32131013071. The next prime is 32131013227. The reversal of 32131013153 is 35131013123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32072153569 + 58859584 = 179087^2 + 7672^2 .

It is an emirp because it is prime and its reverse (35131013123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32131013153 - 216 = 32130947617 is a prime.

It is not a weakly prime, because it can be changed into another prime (32131013653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065506576 + 16065506577.

It is an arithmetic number, because the mean of its divisors is an integer number (16065506577).

Almost surely, 232131013153 is an apocalyptic number.

It is an amenable number.

32131013153 is a deficient number, since it is larger than the sum of its proper divisors (1).

32131013153 is an equidigital number, since it uses as much as digits as its factorization.

32131013153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 810, while the sum is 23.

Adding to 32131013153 its reverse (35131013123), we get a palindrome (67262026276).

The spelling of 32131013153 in words is "thirty-two billion, one hundred thirty-one million, thirteen thousand, one hundred fifty-three".