321312113 has 2 divisors, whose sum is σ = 321312114. Its totient is φ = 321312112.

The previous prime is 321312091. The next prime is 321312127. The reversal of 321312113 is 311213123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 185286544 + 136025569 = 13612^2 + 11663^2 .

It is a cyclic number.

It is not a de Polignac number, because 321312113 - 2⁶ = 321312049 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 321312091 and 321312100.

It is not a weakly prime, because it can be changed into another prime (321312143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160656056 + 160656057.

It is an arithmetic number, because the mean of its divisors is an integer number (160656057).

Almost surely, 2^321312113 is an apocalyptic number.

It is an amenable number.

321312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

321312113 is an equidigital number, since it uses as much as digits as its factorization.

321312113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108, while the sum is 17.

The square root of 321312113 is about 17925.1809753765. The cubic root of 321312113 is about 684.9239711736.

Adding to 321312113 its reverse (311213123), we get a palindrome (632525236).

The spelling of 321312113 in words is "three hundred twenty-one million, three hundred twelve thousand, one hundred thirteen".