Base | Representation |
---|---|
bin | 101110110000011101100… |
… | …010110011011000000000 |
3 | 102101011122122020000222021 |
4 | 232300131202303120000 |
5 | 410120443041400000 |
6 | 10500031520451224 |
7 | 451066246365031 |
oct | 56603542633000 |
9 | 12334578200867 |
10 | 3213131200000 |
11 | 1029754883887 |
12 | 43a887179b14 |
13 | 1a3cc64697b7 |
14 | b1732d36a88 |
15 | 588aa8d411a |
hex | 2ec1d8b3600 |
3213131200000 has 240 divisors, whose sum is σ = 8040808824048. Its totient is φ = 1282636800000.
The previous prime is 3213131199959. The next prime is 3213131200003. The reversal of 3213131200000 is 21313123.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3213131200003) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 913598242 + ... + 913601758.
Almost surely, 23213131200000 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3213131200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4020404412024).
3213131200000 is an abundant number, since it is smaller than the sum of its proper divisors (4827677624048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3213131200000 is an frugal number, since it uses more digits than its factorization.
3213131200000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4131 (or 4095 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 3213131200000 its reverse (21313123), we get a palindrome (3213152513123).
The spelling of 3213131200000 in words is "three trillion, two hundred thirteen billion, one hundred thirty-one million, two hundred thousand".
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