Base | Representation |
---|---|
bin | 11101111011001011… |
… | …100111000111011001 |
3 | 10001221021220212120122 |
4 | 131323023213013121 |
5 | 1011301120144231 |
6 | 22432211403025 |
7 | 2215150333202 |
oct | 357313470731 |
9 | 101837825518 |
10 | 32131412441 |
11 | 12699387817 |
12 | 62888b3475 |
13 | 3050b30aab |
14 | 17ab5505a9 |
15 | c80ce877b |
hex | 77b2e71d9 |
32131412441 has 2 divisors, whose sum is σ = 32131412442. Its totient is φ = 32131412440.
The previous prime is 32131412399. The next prime is 32131412503. The reversal of 32131412441 is 14421413123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32100097225 + 31315216 = 179165^2 + 5596^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32131412441 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 32131412441.
It is not a weakly prime, because it can be changed into another prime (32131412041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065706220 + 16065706221.
It is an arithmetic number, because the mean of its divisors is an integer number (16065706221).
Almost surely, 232131412441 is an apocalyptic number.
It is an amenable number.
32131412441 is a deficient number, since it is larger than the sum of its proper divisors (1).
32131412441 is an equidigital number, since it uses as much as digits as its factorization.
32131412441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2304, while the sum is 26.
Adding to 32131412441 its reverse (14421413123), we get a palindrome (46552825564).
The spelling of 32131412441 in words is "thirty-two billion, one hundred thirty-one million, four hundred twelve thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •