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321330140040977 is a prime number
BaseRepresentation
bin100100100001111111000000…
…0110110100100111100010001
31120010201212020221120021012222
41021003332000312210330101
5314104133111322302402
63055225010051430425
7124453223264353064
oct11103760066447421
91503655227507188
10321330140040977
119342738aaa2621
1230057b258b5415
1310a3b3c0b9ac52
14594c6670dc8db
1527238036a77a2
hex1243f80da4f11

321330140040977 has 2 divisors, whose sum is σ = 321330140040978. Its totient is φ = 321330140040976.

The previous prime is 321330140040967. The next prime is 321330140041067. The reversal of 321330140040977 is 779040041033123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 268388567039761 + 52941573001216 = 16382569^2 + 7276096^2 .

It is an emirp because it is prime and its reverse (779040041033123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 321330140040977 - 24 = 321330140040961 is a prime.

It is a super-2 number, since 2×3213301400409772 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (321330140040967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160665070020488 + 160665070020489.

It is an arithmetic number, because the mean of its divisors is an integer number (160665070020489).

Almost surely, 2321330140040977 is an apocalyptic number.

It is an amenable number.

321330140040977 is a deficient number, since it is larger than the sum of its proper divisors (1).

321330140040977 is an equidigital number, since it uses as much as digits as its factorization.

321330140040977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 381024, while the sum is 44.

The spelling of 321330140040977 in words is "three hundred twenty-one trillion, three hundred thirty billion, one hundred forty million, forty thousand, nine hundred seventy-seven".