Base | Representation |
---|---|
bin | 101110110000100111101… |
… | …110111001010100010111 |
3 | 102101012002112212210122000 |
4 | 232300213232321110113 |
5 | 410121320322022411 |
6 | 10500100504410343 |
7 | 451103423356626 |
oct | 56604756712427 |
9 | 12335075783560 |
10 | 3213302142231 |
11 | 102983231a255 |
12 | 43a9144769b3 |
13 | 1a40229bb94c |
14 | b174b9136bd |
15 | 588ba8ed956 |
hex | 2ec27bb9517 |
3213302142231 has 32 divisors (see below), whose sum is σ = 4835448683520. Its totient is φ = 2108700037152.
The previous prime is 3213302142179. The next prime is 3213302142251. The reversal of 3213302142231 is 1322412033123.
3213302142231 is a `hidden beast` number, since 3 + 213 + 3 + 0 + 21 + 422 + 3 + 1 = 666.
3213302142231 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3213302142231 - 27 = 3213302142103 is a prime.
It is a super-2 number, since 2×32133021422312 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 3213302142195 and 3213302142204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3213302142251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2995000 + ... + 3923853.
It is an arithmetic number, because the mean of its divisors is an integer number (151107771360).
Almost surely, 23213302142231 is an apocalyptic number.
3213302142231 is a deficient number, since it is larger than the sum of its proper divisors (1622146541289).
3213302142231 is a wasteful number, since it uses less digits than its factorization.
3213302142231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6919132 (or 6919126 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 3213302142231 its reverse (1322412033123), we get a palindrome (4535714175354).
It can be divided in two parts, 3213302 and 142231, that added together give a palindrome (3355533).
The spelling of 3213302142231 in words is "three trillion, two hundred thirteen billion, three hundred two million, one hundred forty-two thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •