Base | Representation |
---|---|
bin | 1110100111001100011110… |
… | …10110101111010000111111 |
3 | 11012202220000212211111022202 |
4 | 13103212033112233100333 |
5 | 13202431444143202111 |
6 | 152201415532102115 |
7 | 6524352032454563 |
oct | 723461726572077 |
9 | 135686025744282 |
10 | 32133055444031 |
11 | a269609100323 |
12 | 372b72730493b |
13 | 14c11988a2999 |
14 | 7d13690216a3 |
15 | 3aacc3eb1b3b |
hex | 1d398f5af43f |
32133055444031 has 4 divisors (see below), whose sum is σ = 32145149182272. Its totient is φ = 32120961705792.
The previous prime is 32133055443989. The next prime is 32133055444057. The reversal of 32133055444031 is 13044455033123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 32133055444031 - 222 = 32133051249727 is a prime.
It is a super-2 number, since 2×321330554440312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32133055444331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6046865135 + ... + 6046870448.
It is an arithmetic number, because the mean of its divisors is an integer number (8036287295568).
Almost surely, 232133055444031 is an apocalyptic number.
32133055444031 is a deficient number, since it is larger than the sum of its proper divisors (12093738241).
32133055444031 is a wasteful number, since it uses less digits than its factorization.
32133055444031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12093738240.
The product of its (nonzero) digits is 259200, while the sum is 38.
The spelling of 32133055444031 in words is "thirty-two trillion, one hundred thirty-three billion, fifty-five million, four hundred forty-four thousand, thirty-one".
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