Base | Representation |
---|---|
bin | 111101010010… |
… | …0111111111001 |
3 | 2020110112100022 |
4 | 1322210333321 |
5 | 31211224423 |
6 | 3104420225 |
7 | 540061355 |
oct | 172447771 |
9 | 66415308 |
10 | 32133113 |
11 | 171580a1 |
12 | a917675 |
13 | 6870b9c |
14 | 43a6465 |
15 | 2c4adc8 |
hex | 1ea4ff9 |
32133113 has 2 divisors, whose sum is σ = 32133114. Its totient is φ = 32133112.
The previous prime is 32133103. The next prime is 32133173. The reversal of 32133113 is 31133123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32126224 + 6889 = 5668^2 + 83^2 .
It is a cyclic number.
It is not a de Polignac number, because 32133113 - 24 = 32133097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32133091 and 32133100.
It is not a weakly prime, because it can be changed into another prime (32133103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16066556 + 16066557.
It is an arithmetic number, because the mean of its divisors is an integer number (16066557).
Almost surely, 232133113 is an apocalyptic number.
It is an amenable number.
32133113 is a deficient number, since it is larger than the sum of its proper divisors (1).
32133113 is an equidigital number, since it uses as much as digits as its factorization.
32133113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 162, while the sum is 17.
The square root of 32133113 is about 5668.6076773755. The cubic root of 32133113 is about 317.9198174750.
Adding to 32133113 its reverse (31133123), we get a palindrome (63266236).
The spelling of 32133113 in words is "thirty-two million, one hundred thirty-three thousand, one hundred thirteen".
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