Base | Representation |
---|---|
bin | 1110100111001100100110… |
… | …10001100111011011110111 |
3 | 11012202220012110120202102012 |
4 | 13103212103101213123313 |
5 | 13202432113012210403 |
6 | 152201430241434435 |
7 | 6524353461455444 |
oct | 723462321473367 |
9 | 135686173522365 |
10 | 32133121210103 |
11 | a26964223a351 |
12 | 372b74533ba1b |
13 | 14c11a93bb314 |
14 | 7d1373a609cb |
15 | 3aacc9b52ed8 |
hex | 1d39934676f7 |
32133121210103 has 4 divisors (see below), whose sum is σ = 32739406516008. Its totient is φ = 31526835904200.
The previous prime is 32133121210063. The next prime is 32133121210109. The reversal of 32133121210103 is 30101212133123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 32133121210103 - 222 = 32133117015799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32133121210109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 303142652873 + ... + 303142652978.
It is an arithmetic number, because the mean of its divisors is an integer number (8184851629002).
Almost surely, 232133121210103 is an apocalyptic number.
32133121210103 is a deficient number, since it is larger than the sum of its proper divisors (606285305905).
32133121210103 is an equidigital number, since it uses as much as digits as its factorization.
32133121210103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 606285305904.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 32133121210103 its reverse (30101212133123), we get a palindrome (62234333343226).
The spelling of 32133121210103 in words is "thirty-two trillion, one hundred thirty-three billion, one hundred twenty-one million, two hundred ten thousand, one hundred three".
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