Base | Representation |
---|---|
bin | 1110100111001110001111… |
… | …11101110011111110100011 |
3 | 11012202222111001222122201202 |
4 | 13103213013331303332203 |
5 | 13202440420313223133 |
6 | 152202054100551415 |
7 | 6524414414400611 |
oct | 723470775637643 |
9 | 135688431878652 |
10 | 32134005211043 |
11 | a269a5623433a |
12 | 372b9513b256b |
13 | 14c12ba5a26b8 |
14 | 7d14192146b1 |
15 | 3aad2c56e2e8 |
hex | 1d39c7f73fa3 |
32134005211043 has 2 divisors, whose sum is σ = 32134005211044. Its totient is φ = 32134005211042.
The previous prime is 32134005210971. The next prime is 32134005211123. The reversal of 32134005211043 is 34011250043123.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 32134005211043 - 28 = 32134005210787 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32134005210997 and 32134005211015.
It is not a weakly prime, because it can be changed into another prime (32134005211643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16067002605521 + 16067002605522.
It is an arithmetic number, because the mean of its divisors is an integer number (16067002605522).
Almost surely, 232134005211043 is an apocalyptic number.
32134005211043 is a deficient number, since it is larger than the sum of its proper divisors (1).
32134005211043 is an equidigital number, since it uses as much as digits as its factorization.
32134005211043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 32134005211043 its reverse (34011250043123), we get a palindrome (66145255254166).
The spelling of 32134005211043 in words is "thirty-two trillion, one hundred thirty-four billion, five million, two hundred eleven thousand, forty-three".
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