Base | Representation |
---|---|
bin | 1110100111011011101110… |
… | …01110110010111101110011 |
3 | 11012210200011022201201001112 |
4 | 13103231313032302331303 |
5 | 13203100230101042233 |
6 | 152205252045223535 |
7 | 6525061622506661 |
oct | 723556716627563 |
9 | 135720138651045 |
10 | 32141240643443 |
11 | a272029471838 |
12 | 3731230561bab |
13 | 14c1ba15ba449 |
14 | 7d1904137c31 |
15 | 3ab102891048 |
hex | 1d3b773b2f73 |
32141240643443 has 2 divisors, whose sum is σ = 32141240643444. Its totient is φ = 32141240643442.
The previous prime is 32141240643377. The next prime is 32141240643511. The reversal of 32141240643443 is 34434604214123.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 32141240643443 - 214 = 32141240627059 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 32141240643443.
It is not a weakly prime, because it can be changed into another prime (32141240543443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16070620321721 + 16070620321722.
It is an arithmetic number, because the mean of its divisors is an integer number (16070620321722).
Almost surely, 232141240643443 is an apocalyptic number.
32141240643443 is a deficient number, since it is larger than the sum of its proper divisors (1).
32141240643443 is an equidigital number, since it uses as much as digits as its factorization.
32141240643443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 663552, while the sum is 41.
Adding to 32141240643443 its reverse (34434604214123), we get a palindrome (66575844857566).
The spelling of 32141240643443 in words is "thirty-two trillion, one hundred forty-one billion, two hundred forty million, six hundred forty-three thousand, four hundred forty-three".
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