Base | Representation |
---|---|
bin | 11101111011110100… |
… | …100010001011010001 |
3 | 10001222001002220011211 |
4 | 131323310202023101 |
5 | 1011311341440423 |
6 | 22433233340121 |
7 | 2215340453206 |
oct | 357364421321 |
9 | 101861086154 |
10 | 32142140113 |
11 | 126a4444666 |
12 | 6290407641 |
13 | 3053118925 |
14 | 17acb43cad |
15 | c81c1710d |
hex | 77bd222d1 |
32142140113 has 2 divisors, whose sum is σ = 32142140114. Its totient is φ = 32142140112.
The previous prime is 32142140083. The next prime is 32142140123. The reversal of 32142140113 is 31104124123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27784555969 + 4357584144 = 166687^2 + 66012^2 .
It is a cyclic number.
It is not a de Polignac number, because 32142140113 - 25 = 32142140081 is a prime.
It is not a weakly prime, because it can be changed into another prime (32142140123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16071070056 + 16071070057.
It is an arithmetic number, because the mean of its divisors is an integer number (16071070057).
Almost surely, 232142140113 is an apocalyptic number.
It is an amenable number.
32142140113 is a deficient number, since it is larger than the sum of its proper divisors (1).
32142140113 is an equidigital number, since it uses as much as digits as its factorization.
32142140113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 32142140113 its reverse (31104124123), we get a palindrome (63246264236).
The spelling of 32142140113 in words is "thirty-two billion, one hundred forty-two million, one hundred forty thousand, one hundred thirteen".
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