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3214400031433 is a prime number
BaseRepresentation
bin101110110001101001001…
…011000000101011001001
3102101021221001202100111001
4232301221023000223021
5410131042402001213
610500401444135001
7451142554312033
oct56615113005311
912337831670431
103214400031433
11102a2460226a8
1243ab80097461
131a41692b0926
14b1813662c53
1558931eb91dd
hex2ec692c0ac9

3214400031433 has 2 divisors, whose sum is σ = 3214400031434. Its totient is φ = 3214400031432.

The previous prime is 3214400031371. The next prime is 3214400031443. The reversal of 3214400031433 is 3341300044123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1711512829504 + 1502887201929 = 1308248^2 + 1225923^2 .

It is a cyclic number.

It is not a de Polignac number, because 3214400031433 - 29 = 3214400030921 is a prime.

It is a super-3 number, since 3×32144000314333 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (3214400031443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607200015716 + 1607200015717.

It is an arithmetic number, because the mean of its divisors is an integer number (1607200015717).

Almost surely, 23214400031433 is an apocalyptic number.

It is an amenable number.

3214400031433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3214400031433 is an equidigital number, since it uses as much as digits as its factorization.

3214400031433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 3214400031433 its reverse (3341300044123), we get a palindrome (6555700075556).

The spelling of 3214400031433 in words is "three trillion, two hundred fourteen billion, four hundred million, thirty-one thousand, four hundred thirty-three".