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3222222220130 = 251126912859343
BaseRepresentation
bin101110111000111011011…
…010010010101101100010
3102102001010012120201010112
4232320323122102231202
5410243102342021010
610504133552531322
7451540445650634
oct56707332225542
912361105521115
103222222220130
11103259a492861
124405a3850b42
131a4b14a38154
14b1d56482a54
1558c3da8ea05
hex2ee3b692b62

3222222220130 has 16 divisors (see below), whose sum is σ = 5800053492864. Its totient is φ = 1288876999920.

The previous prime is 3222222220127. The next prime is 3222222220171. The reversal of 3222222220130 is 310222222223.

It is a super-4 number, since 4×32222222201304 (a number of 51 digits) contains 4444 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3222222220096 and 3222222220105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 302762 + ... + 2556581.

It is an arithmetic number, because the mean of its divisors is an integer number (362503343304).

Almost surely, 23222222220130 is an apocalyptic number.

3222222220130 is a deficient number, since it is larger than the sum of its proper divisors (2577831272734).

3222222220130 is a wasteful number, since it uses less digits than its factorization.

3222222220130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2972041.

The product of its (nonzero) digits is 2304, while the sum is 23.

Adding to 3222222220130 its reverse (310222222223), we get a palindrome (3532444442353).

The spelling of 3222222220130 in words is "three trillion, two hundred twenty-two billion, two hundred twenty-two million, two hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 112691 225382 563455 1126910 2859343 5718686 14296715 28593430 322222222013 644444444026 1611111110065 3222222220130