Base | Representation |
---|---|
bin | 101110111001110000111… |
… | …111101010101010101001 |
3 | 102102010102212012010102120 |
4 | 232321300333222222221 |
5 | 410301423012210100 |
6 | 10504403105221453 |
7 | 451601643151503 |
oct | 56716077525251 |
9 | 12363385163376 |
10 | 3223121210025 |
11 | 1032a10995212 |
12 | 4407b4931889 |
13 | 1a4c29069b32 |
14 | b1ddda18d73 |
15 | 58c9296c0a0 |
hex | 2ee70feaaa9 |
3223121210025 has 12 divisors (see below), whose sum is σ = 5328893734032. Its totient is φ = 1718997978640.
The previous prime is 3223121210011. The next prime is 3223121210033. The reversal of 3223121210025 is 5200121213223.
It is not a de Polignac number, because 3223121210025 - 217 = 3223121078953 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3223121209977 and 3223121210004.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 21487474659 + ... + 21487474808.
It is an arithmetic number, because the mean of its divisors is an integer number (444074477836).
Almost surely, 23223121210025 is an apocalyptic number.
It is an amenable number.
3223121210025 is a deficient number, since it is larger than the sum of its proper divisors (2105772524007).
3223121210025 is a wasteful number, since it uses less digits than its factorization.
3223121210025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42974949480 (or 42974949475 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 3223121210025 its reverse (5200121213223), we get a palindrome (8423242423248).
The spelling of 3223121210025 in words is "three trillion, two hundred twenty-three billion, one hundred twenty-one million, two hundred ten thousand, twenty-five".
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