Search a number
-
+
32240413251457 is a prime number
BaseRepresentation
bin1110101010010100011100…
…11000010001011110000001
311020011011010211111011212121
413111022032120101132001
513211211331243021312
6152323012534324241
76535202331664645
oct725121630213601
9136134124434777
1032240413251457
11a30009a858004
1237484a91b9681
1314cb347876118
147d663133cc25
153ad9a9142707
hex1d528e611781

32240413251457 has 2 divisors, whose sum is σ = 32240413251458. Its totient is φ = 32240413251456.

The previous prime is 32240413251407. The next prime is 32240413251467. The reversal of 32240413251457 is 75415231404223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23494174832241 + 8746238419216 = 4847079^2 + 2957404^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32240413251457 is a prime.

It is not a weakly prime, because it can be changed into another prime (32240413251407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16120206625728 + 16120206625729.

It is an arithmetic number, because the mean of its divisors is an integer number (16120206625729).

Almost surely, 232240413251457 is an apocalyptic number.

It is an amenable number.

32240413251457 is a deficient number, since it is larger than the sum of its proper divisors (1).

32240413251457 is an equidigital number, since it uses as much as digits as its factorization.

32240413251457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 806400, while the sum is 43.

The spelling of 32240413251457 in words is "thirty-two trillion, two hundred forty billion, four hundred thirteen million, two hundred fifty-one thousand, four hundred fifty-seven".