Base | Representation |
---|---|
bin | 1110101010010100011100… |
… | …11000010001011110000001 |
3 | 11020011011010211111011212121 |
4 | 13111022032120101132001 |
5 | 13211211331243021312 |
6 | 152323012534324241 |
7 | 6535202331664645 |
oct | 725121630213601 |
9 | 136134124434777 |
10 | 32240413251457 |
11 | a30009a858004 |
12 | 37484a91b9681 |
13 | 14cb347876118 |
14 | 7d663133cc25 |
15 | 3ad9a9142707 |
hex | 1d528e611781 |
32240413251457 has 2 divisors, whose sum is σ = 32240413251458. Its totient is φ = 32240413251456.
The previous prime is 32240413251407. The next prime is 32240413251467. The reversal of 32240413251457 is 75415231404223.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23494174832241 + 8746238419216 = 4847079^2 + 2957404^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32240413251457 is a prime.
It is not a weakly prime, because it can be changed into another prime (32240413251407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16120206625728 + 16120206625729.
It is an arithmetic number, because the mean of its divisors is an integer number (16120206625729).
Almost surely, 232240413251457 is an apocalyptic number.
It is an amenable number.
32240413251457 is a deficient number, since it is larger than the sum of its proper divisors (1).
32240413251457 is an equidigital number, since it uses as much as digits as its factorization.
32240413251457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 43.
The spelling of 32240413251457 in words is "thirty-two trillion, two hundred forty billion, four hundred thirteen million, two hundred fifty-one thousand, four hundred fifty-seven".
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