Base | Representation |
---|---|
bin | 101110111011101101101… |
… | …111100110110101001011 |
3 | 102102022211201102121002102 |
4 | 232323231233212311023 |
5 | 410320214310331021 |
6 | 10505350512224015 |
7 | 452004545651255 |
oct | 56735557466513 |
9 | 12368751377072 |
10 | 3225214152011 |
11 | 1033895342535 |
12 | 44109983b00b |
13 | 1a51a0856247 |
14 | b215b988cd5 |
15 | 58d6658d00b |
hex | 2eeedbe6d4b |
3225214152011 has 2 divisors, whose sum is σ = 3225214152012. Its totient is φ = 3225214152010.
The previous prime is 3225214151989. The next prime is 3225214152067. The reversal of 3225214152011 is 1102514125223.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3225214152011 - 210 = 3225214150987 is a prime.
It is not a weakly prime, because it can be changed into another prime (3225214152071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1612607076005 + 1612607076006.
It is an arithmetic number, because the mean of its divisors is an integer number (1612607076006).
Almost surely, 23225214152011 is an apocalyptic number.
3225214152011 is a deficient number, since it is larger than the sum of its proper divisors (1).
3225214152011 is an equidigital number, since it uses as much as digits as its factorization.
3225214152011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 3225214152011 its reverse (1102514125223), we get a palindrome (4327728277234).
The spelling of 3225214152011 in words is "three trillion, two hundred twenty-five billion, two hundred fourteen million, one hundred fifty-two thousand, eleven".
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