Base | Representation |
---|---|
bin | 101111000000100011000… |
… | …010101110000011000111 |
3 | 102102211020100202202011112 |
4 | 233000203002232003013 |
5 | 410411331222301210 |
6 | 10512005442155235 |
7 | 452250256116020 |
oct | 57004302560307 |
9 | 12384210682145 |
10 | 3230403322055 |
11 | 1036008505818 |
12 | 4420a7652b1b |
13 | 1a5819949870 |
14 | b24d0c0dc47 |
15 | 5906be0ed05 |
hex | 2f0230ae0c7 |
3230403322055 has 32 divisors (see below), whose sum is σ = 4771193175168. Its totient is φ = 2044680537600.
The previous prime is 3230403322051. The next prime is 3230403322057. The reversal of 3230403322055 is 5502233040323.
3230403322055 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3230403322055 - 22 = 3230403322051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3230403322051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20478785 + ... + 20635925.
It is an arithmetic number, because the mean of its divisors is an integer number (149099786724).
Almost surely, 23230403322055 is an apocalyptic number.
3230403322055 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3230403322055 is a deficient number, since it is larger than the sum of its proper divisors (1540789853113).
3230403322055 is a wasteful number, since it uses less digits than its factorization.
3230403322055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202347.
The product of its (nonzero) digits is 64800, while the sum is 32.
Adding to 3230403322055 its reverse (5502233040323), we get a palindrome (8732636362378).
The spelling of 3230403322055 in words is "three trillion, two hundred thirty billion, four hundred three million, three hundred twenty-two thousand, fifty-five".
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