3231204012133 has 8 divisors (see below), whose sum is σ = 3232129725720. Its totient is φ = 3230278444800.

The previous prime is 3231204012119. The next prime is 3231204012181. The reversal of 3231204012133 is 3312104021323.

It can be written as a sum of positive squares in 4 ways, for example, as 319669244449 + 2911534767684 = 565393^2 + 1706322^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3231204012133 is a prime.

It is a super-2 number, since 2×3231204012133² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3231204012098 and 3231204012107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3231204012833) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55519473 + ... + 55577641.

It is an arithmetic number, because the mean of its divisors is an integer number (404016215715).

Almost surely, 2^{3231204012133} is an apocalyptic number.

It is an amenable number.

3231204012133 is a deficient number, since it is larger than the sum of its proper divisors (925713587).

3231204012133 is an equidigital number, since it uses as much as digits as its factorization.

3231204012133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73127.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3231204012133 its reverse (3312104021323), we get a palindrome (6543308033456).

The spelling of 3231204012133 in words is "three trillion, two hundred thirty-one billion, two hundred four million, twelve thousand, one hundred thirty-three".