Base | Representation |
---|---|
bin | 101111000010000010011… |
… | …001011110001101111001 |
3 | 102102222100212002000011212 |
4 | 233002002121132031321 |
5 | 410423120244401131 |
6 | 10512432311332505 |
7 | 452335023153641 |
oct | 57020231361571 |
9 | 12388325060155 |
10 | 3232003122041 |
11 | 1036759560171 |
12 | 442473381135 |
13 | 1a5a13212585 |
14 | b2603491521 |
15 | 591125bea2b |
hex | 2f08265e379 |
3232003122041 has 2 divisors, whose sum is σ = 3232003122042. Its totient is φ = 3232003122040.
The previous prime is 3232003122013. The next prime is 3232003122077. The reversal of 3232003122041 is 1402213002323.
3232003122041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3065314646416 + 166688475625 = 1750804^2 + 408275^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3232003122041 is a prime.
It is a super-2 number, since 2×32320031220412 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3232003121998 and 3232003122016.
It is not a weakly prime, because it can be changed into another prime (3232003122091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1616001561020 + 1616001561021.
It is an arithmetic number, because the mean of its divisors is an integer number (1616001561021).
Almost surely, 23232003122041 is an apocalyptic number.
It is an amenable number.
3232003122041 is a deficient number, since it is larger than the sum of its proper divisors (1).
3232003122041 is an equidigital number, since it uses as much as digits as its factorization.
3232003122041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 3232003122041 its reverse (1402213002323), we get a palindrome (4634216124364).
The spelling of 3232003122041 in words is "three trillion, two hundred thirty-two billion, three million, one hundred twenty-two thousand, forty-one".
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