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323213312020177 is a prime number
BaseRepresentation
bin100100101111101011111011…
…0101001100100111011010001
31120101101220001102212202010201
41021133113312221210323101
5314331011330334121202
63103230051250455201
7125036251115152405
oct11137276651447321
91511356042782121
10323213312020177
1193a92aa55331a7
1230300aa4294501
1310b46b66455617
1459b5871a19105
1527577bede5387
hex125f5f6a64ed1

323213312020177 has 2 divisors, whose sum is σ = 323213312020178. Its totient is φ = 323213312020176.

The previous prime is 323213312020163. The next prime is 323213312020217. The reversal of 323213312020177 is 771020213312323.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 232315850931921 + 90897461088256 = 15241911^2 + 9534016^2 .

It is a cyclic number.

It is not a de Polignac number, because 323213312020177 - 215 = 323213311987409 is a prime.

It is a super-2 number, since 2×3232133120201772 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (323213312020777) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161606656010088 + 161606656010089.

It is an arithmetic number, because the mean of its divisors is an integer number (161606656010089).

Almost surely, 2323213312020177 is an apocalyptic number.

It is an amenable number.

323213312020177 is a deficient number, since it is larger than the sum of its proper divisors (1).

323213312020177 is an equidigital number, since it uses as much as digits as its factorization.

323213312020177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63504, while the sum is 37.

The spelling of 323213312020177 in words is "three hundred twenty-three trillion, two hundred thirteen billion, three hundred twelve million, twenty thousand, one hundred seventy-seven".