Base | Representation |
---|---|
bin | 100100110000010100010010… |
… | …1101110010000011101010010 |
3 | 1120101201011210221201101222110 |
4 | 1021200220211232100131102 |
5 | 314333421400241402010 |
6 | 3103333545315050150 |
7 | 125045440262314104 |
oct | 11140504556203522 |
9 | 1511634727641873 |
10 | 323300001122130 |
11 | 9401684024660a |
12 | 303158582a0956 |
13 | 10b520a034b016 |
14 | 59b9b36d01574 |
15 | 2759b9576a120 |
hex | 1260a25b90752 |
323300001122130 has 256 divisors, whose sum is σ = 795093230002176. Its totient is φ = 84116841431040.
The previous prime is 323300001122099. The next prime is 323300001122233. The reversal of 323300001122130 is 31221100003323.
It is a junction number, because it is equal to n+sod(n) for n = 323300001122097 and 323300001122106.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 97291602649 + ... + 97291605971.
It is an arithmetic number, because the mean of its divisors is an integer number (3105832929696).
Almost surely, 2323300001122130 is an apocalyptic number.
323300001122130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
323300001122130 is an abundant number, since it is smaller than the sum of its proper divisors (471793228880046).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
323300001122130 is a wasteful number, since it uses less digits than its factorization.
323300001122130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4961.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 323300001122130 its reverse (31221100003323), we get a palindrome (354521101125453).
The spelling of 323300001122130 in words is "three hundred twenty-three trillion, three hundred billion, one million, one hundred twenty-two thousand, one hundred thirty".
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