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323303110311257 is a prime number
BaseRepresentation
bin100100110000010101101111…
…1000010110111110101011001
31120101201110211122012120122022
41021200223133002313311121
5314333444232214430012
63103335222023504225
7125045610315063326
oct11140533702676531
91511643748176568
10323303110311257
11940180963043aa
12303163855b8075
1310b524775427bb
1459b9d4dc0bb4d
152759cc86cb472
hex1260adf0b7d59

323303110311257 has 2 divisors, whose sum is σ = 323303110311258. Its totient is φ = 323303110311256.

The previous prime is 323303110311221. The next prime is 323303110311319. The reversal of 323303110311257 is 752113011303323.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 323294028983641 + 9081327616 = 17980379^2 + 95296^2 .

It is an emirp because it is prime and its reverse (752113011303323) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 323303110311257 - 220 = 323303109262681 is a prime.

It is a super-2 number, since 2×3233031103112572 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (323303110311217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161651555155628 + 161651555155629.

It is an arithmetic number, because the mean of its divisors is an integer number (161651555155629).

Almost surely, 2323303110311257 is an apocalyptic number.

It is an amenable number.

323303110311257 is a deficient number, since it is larger than the sum of its proper divisors (1).

323303110311257 is an equidigital number, since it uses as much as digits as its factorization.

323303110311257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34020, while the sum is 35.

The spelling of 323303110311257 in words is "three hundred twenty-three trillion, three hundred three billion, one hundred ten million, three hundred eleven thousand, two hundred fifty-seven".